Heat Exchanger LMTD Calculator (Log Mean Temperature Difference) | Online Free Tool | Elysia Tools
Elysia Tools
Navigation
Math & Numbers
Heat Exchanger LMTD Calculator (Log Mean Temperature Difference)
Compute the Log Mean Temperature Difference (LMTD) of a heat exchanger for parallel or counter flow. Parallel flow: ΔT₁ = T_h,in - T_c,in and ΔT₂ = T_h,out - T_c,out; counter flow: ΔT₁ = T_h,in - T_c,out and ΔT₂ = T_h,out - T_c,in. LMTD = (ΔT₁ - ΔT₂)/ln(ΔT₁/ΔT₂), or ΔT₁ when ΔT₁ = ΔT₂. A non-positive terminal difference (temperature cross) is physically impossible and is rejected. Optionally, with the overall heat transfer coefficient U (W/(m²·K)) and the heat transfer area A (m²), the heat transfer rate Q = U·A·LMTD (W) is returned. Temperatures are used only as differences: Δ°C = ΔK and Δ°F ×5/9 = ΔK; the LMTD is reported in K.
Execution
Run this tool
Fill in the form, run the tool, and review the result in one place.
Samples
Examples that match this tool
Related
Continue with connected tools and hubs
Result
Ready for a run
Run the tool to preview files, text, structured data, or streamed output here.
Learn when to use this tool, what it supports, and how real users apply it.
Key facts
Category
Math & Numbers
Input types
select, number
Output type
json
Sample coverage
4
API ready
Yes
Overview
Calculate the log mean temperature difference (LMTD) for parallel-flow or counter-flow heat exchangers using four stream temperatures. The calculator reports LMTD in K and can also calculate heat transfer rate when overall heat transfer coefficient U and area A are provided.
When to use
Estimate the effective temperature driving force in a heat exchanger.
Compare LMTD for parallel-flow and counter-flow arrangements.
Calculate heat transfer rate from U, A, and LMTD during thermal design.
How it works
1Enter the hot-stream inlet and outlet temperatures and the cold-stream inlet and outlet temperatures.
2Select parallel flow or counter flow and choose K, °C, or °F as the input temperature unit.
3The calculator determines the two terminal temperature differences and applies the LMTD formula.
4Optionally enter U in W/(m²·K) and A in m² to calculate Q = U·A·LMTD in watts.
Use cases
Thermal design of shell-and-tube and other heat exchangers.
Preliminary sizing checks using an overall heat transfer coefficient and heat transfer area.
Engineering review of inlet and outlet temperature measurements for counter-flow or parallel-flow equipment.
Examples
1. Counter-flow LMTD calculation
Thermal engineer
Background
An engineer is checking the temperature driving force for a counter-flow heat exchanger with known stream inlet and outlet temperatures.
Problem
Find the two terminal temperature differences and the resulting LMTD.
How to use
Select Counter Flow, enter hot-stream temperatures of 100 °C and 60 °C, and cold-stream temperatures of 20 °C and 50 °C.
The terminal differences are 50 K and 40 K, producing an LMTD of approximately 44.8142 K.
2. Parallel-flow heat transfer rate
Process design engineer
Background
A process designer wants to estimate the heat transfer rate for a parallel-flow exchanger using its overall coefficient and area.
Problem
Calculate both LMTD and Q from the stream temperatures, U, and A.
How to use
Select Parallel Flow, enter hot-stream temperatures of 120 °C and 70 °C, cold-stream temperatures of 30 °C and 60 °C, U of 500 W/(m²·K), and A of 2 m².
FAQ
What does the LMTD calculator calculate?
It calculates the log mean temperature difference of a heat exchanger for parallel-flow or counter-flow operation.
What temperature inputs are required?
You need the hot-stream inlet and outlet temperatures and the cold-stream inlet and outlet temperatures.
What units does the calculator use for LMTD?
The result is reported in kelvin (K). Temperature differences in °C equal differences in K, while Fahrenheit differences are converted to K.
Can it calculate heat transfer rate?
Yes. Enter both U and A to calculate Q = U·A·LMTD in watts.
What happens if a terminal temperature difference is zero or negative?
The calculator rejects the input because a non-positive terminal difference indicates a physically impossible temperature cross.