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Calculate engineering stress σ = F/A and engineering strain ε = ΔL/L₀ under uniaxial load. Choose what to solve: for stress, enter force F (N) and cross-section area A (mm²) → result in MPa; for strain, enter original length L₀ and elongation ΔL (negative for compression) → dimensionless ratio. Units are self-consistent (N, mm) so stress comes out directly in MPa.
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Calculate engineering stress or strain for a uniaxial load using σ = F/A or ε = ΔL/L₀. Enter force and cross-section area for stress in MPa, or original length and elongation for a dimensionless strain result.
Background
A tensile test applies an axial force of 10,000 N to a specimen with a 50 mm² cross-section.
Problem
Find the engineering stress in MPa and identify the loading direction.
How to use
Select Stress, enter F = 10000 and A = 50, then choose the required decimal precision.
{"solveFor":"stress","F":10000,"A":50,"decimalPlaces":4}Outcome
The result is 200.0000 MPa under tension.
Background
A specimen with an original length of 200 mm shortens by 0.4 mm under load.
Problem
Calculate the engineering strain and confirm that the negative value represents compression.
How to use
Select Strain, enter L₀ = 200 and ΔL = -0.4, then set the decimal places.
The calculator uses engineering stress σ = F/A, where F is force in newtons and A is cross-section area in mm².
The calculator uses engineering strain ε = ΔL/L₀, where ΔL is the change in length and L₀ is the original length.
With force in N and area in mm², stress is returned directly in MPa.
Enter a negative elongation ΔL for compression. The resulting strain is negative and the loading is identified as compression.
Select Stress and enter axial force F in N plus cross-section area A in mm².
{"solveFor":"strain","L":200,"dL":-0.4,"decimalPlaces":4}Outcome
The result is ε = -0.0020, identified as compression.