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Math & Numbers

Specific Heat Capacity Converter (J/(kg·K) / kcal / BTU)

· Last updated：2026-07-27

Convert specific heat capacity between J/(kg·K) (joule per kilogram-kelvin, SI base, = J/(kg·°C)), kcal/(kg·°C) (1 = 4186.8 J/(kg·K)), and BTU/(lb·°F) (1 = 4186.8 J/(kg·K)). Key identity: 1 kcal/(kg·°C) = 1 BTU/(lb·°F) — numerically equal because the energy/mass·temperature factors cancel. Converts via J/(kg·K) and lists all three equivalents. Reference values: water ≈ 4186, air cp ≈ 1005, aluminum ≈ 900, iron ≈ 450 J/(kg·K).

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Written by the Elysia Tools team

Tool usage guide

Learn when to use this tool, what it supports, and how real users apply it.

Key facts

Category
Math & Numbers
Input types
select, number
Output type
json
Sample coverage
4
API ready
Yes

Overview

Convert specific heat capacity between J/(kg·K), kcal/(kg·°C), and BTU/(lb·°F). Enter a non-negative value, select the input and output units, and receive the converted result plus equivalent values in all three units.

When to use

  • Convert SI specific heat values such as water, air, aluminum, or iron into kcal or BTU units.
  • Translate engineering and thermodynamics data between metric and BTU-based notation.
  • Check calorimetry or heat-transfer calculations when source data uses a different specific heat unit.

How it works

  1. 1Enter a non-negative specific heat capacity value.
  2. 2Select the input unit: J/(kg·K), kcal/(kg·°C), or BTU/(lb·°F).
  3. 3Select the desired output unit and choose the number of decimal places from 0 to 10.
  4. 4The converter calculates through J/(kg·K) and returns the requested value with all three unit equivalents.

Use cases

  • Compare material properties in heat-transfer and thermodynamics calculations.
  • Convert air or water specific heat values for HVAC, energy, and calorimetry work.
  • Standardize material data before checking calculations that mix SI, kcal, and BTU units.

Examples

1. Water specific heat conversion

Thermodynamics student

Background

A student has the reference specific heat of water in SI units and needs the equivalent kcal and BTU notation.

Problem

Convert 4186.8 J/(kg·K) into kcal/(kg·°C) and review the corresponding BTU value.

How to use

Enter 4186.8, select J/(kg·K) as the input unit, choose kcal/(kg·°C) as the output unit, and set 4 decimal places.

{"inputUnit":"J/(kg·K)","value":4186.8,"outputUnit":"kcal/(kg·°C)","decimalPlaces":4}

Outcome

The result is 1 kcal/(kg·°C), with the full equivalents listed as 4186.8 J/(kg·K), 1 kcal/(kg·°C), and 1 BTU/(lb·°F).

2. Air specific heat in SI units

HVAC engineer

Background

An HVAC reference gives air specific heat as approximately 0.240 BTU/(lb·°F), while the calculation uses SI units.

Problem

Convert the air value to J/(kg·K) and confirm its kcal equivalent.

How to use

Enter 0.24, select BTU/(lb·°F) as the input unit, choose J/(kg·K) as the output unit, and set 4 decimal places.

FAQ

Which specific heat units are supported?

The tool supports J/(kg·K), kcal/(kg·°C), and BTU/(lb·°F).

Are kcal/(kg·°C) and BTU/(lb·°F) numerically equal?

Yes. In this converter, 1 kcal/(kg·°C) equals 1 BTU/(lb·°F) numerically.

What is the conversion basis?

Conversions use J/(kg·K), with 1 kcal/(kg·°C) and 1 BTU/(lb·°F) equal to 4186.8 J/(kg·K).

Can I enter zero or a negative value?

Zero is allowed, but the value must not be negative.

How many decimal places can the result use?

You can select between 0 and 10 decimal places.

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{"inputUnit":"BTU/(lb·°F)","value":0.24,"outputUnit":"J/(kg·K)","decimalPlaces":4}

Outcome

The converter returns 1004.832 J/(kg·K), with equivalent values of 0.24 kcal/(kg·°C) and 0.24 BTU/(lb·°F).